3/(2x-1)^2=27

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Solution for 3/(2x-1)^2=27 equation:


D( x )

(2*x-1)^2 = 0

(2*x-1)^2 = 0

(2*x-1)^2 = 0

2*x-1 = 0 // + 1

2*x = 1 // : 2

x = 1/2

x in (-oo:1/2) U (1/2:+oo)

3/((2*x-1)^2) = 27 // - 27

3/((2*x-1)^2)-27 = 0

3/((2*x-1)^2)+(-27*(2*x-1)^2)/((2*x-1)^2) = 0

3-27*(2*x-1)^2 = 0

108*x-108*x^2-24 = 0

108*x-108*x^2-24 = 0

12*(9*x-9*x^2-2) = 0

9*x-9*x^2-2 = 0

DELTA = 9^2-(-9*(-2)*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)-9)/(-9*2) or x = (-9^(1/2)-9)/(-9*2)

x = 1/3 or x = 2/3

12*(x-1/3)*(x-2/3) = 0

(12*(x-1/3)*(x-2/3))/((2*x-1)^2) = 0

(12*(x-1/3)*(x-2/3))/((2*x-1)^2) = 0 // * (2*x-1)^2

12*(x-1/3)*(x-2/3) = 0

( 12 )

12 = 0

x belongs to the empty set

( x-1/3 )

x-1/3 = 0 // + 1/3

x = 1/3

( x-2/3 )

x-2/3 = 0 // + 2/3

x = 2/3

x in { 1/3, 2/3 }

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